Tagged: branchingflows, compressibility, incompressibility, massflow
 This topic has 0 replies, 1 voice, and was last updated 10 months, 1 week ago by freixas.

AuthorPosts

September 21, 2020 at 4:13 pm #269freixasKeymaster
Please read The Compressibility of Air and Mass Flow, Speed, and Pressure before proceeding.
I introduced some basic fluid dynamics concepts in prior posts. We can apply these in any situation where we have a single air inlet and outlet, such as when we play a single note on the melodica. If we want to understand what happens when more than one note is played, we need to study the physics of branching flows.
Unfortunately, the physics of branching flows gets very complicated, very quickly. I’ll cover what I currently understand now and may expand this topic in the future.
Let’s diagram a very simple branched flow:
Here a single flow is split into two equal flows of half the size. Without thinking too hard, it’s easy to figure out that each branch will get half of the mass flow and that the air’s velocity will be unchanged.
Let’s return to the basic principle that was goes in, comes out. For a branched flow like this we would say: $$\begin{align*}V_1 &= V_2 + V_3\\A_1 v_1 t &= A_2 v_2 t + A_3 v_3 t\\A_1 v_1 &= A_2 v_2 + A_3 v_3\end{align*}$$
What’s interesting is that, even if A_{2} and A_{3} are half the size of A_{1} and we know v_{1}, it still doesn’t tell us much about v_{2} or v_{3}: $$\begin{align*}A_1 v_1 &= A_2 v_2 + A_3 v_3\\A_1 v_1 &= \frac {1}{2}A_1 v_2 + \frac {1}{2}A_1 v_3\\A_1 v_1 &= \frac {1}{2}A_1 ( v_2 + v_3)\\v_1 &= \frac {1}{2} ( v_2 + v_3)\end{align*}$$
If $v_1 = v_2 = v_3$, the equation would be true, but it would be equally true if $v_2 = 0$ and $v_3 = 2v_1$ and for many other values (v_{2} would be 0 if, for example, I capped the end of the A_{2} branch).
Let’s look at a slightly more complex branch.
Again, we would guess that, barring any downstream blockages, that while the mass flows would be divided unequally, all flow velocities would remain the same.
Here’s another simple case:
It looks like the mass flows are divided evenly, but the velocities at A_{2} and A_{3} will be slower (but equal) because the branches have increased the crosssectional area of the system.
Now that we’re nice and overconfident, let’s try this branch:
Branch A_{3} narrows, but only after A_{1} splits into A_{2} and A_{3}. Will this affect what happens at the branch? Yes. The degree to which the narrowing will affect the flow at the branch will depend on the distance from the split to where the one branch narrows. And determining the mass flows requires a lot of mathematics.
Why do we care? As I noted earlier, we may want to understand what happens when two notes are played. Here is a rough diagram of a melodica (not to scale) showing this:
This is still a branched flow. The branching is not clear cut, Branch A_{2} is closer to the air source than branch A_{3}. Branch A_{2} is also bigger than A_{3}. There is also no guarantee that air that heads toward A_{3 }won’t turn around and head back to A_{2}. Further analysis would get us out of the realm of a background article.
There are two things you should retain from this post:
 The air that goes into a system of branched flows is still exactly the same as the air that goes out, just as when we work with a single tube or pipe.
 Simplistic ways of deciding how the mass flow is divided at a branch will probably not work except for the most basic cases.

AuthorPosts
 You must be logged in to reply to this topic.